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return source.val == target.val and ((self.is_inversion(source.left,target.left) and self.is_inversion(source.right,target.right)) or (self.is_inversion(source.left,target.right) and self.is_inversion(source.right,target.left)))
def solve(self, source, target):
dfs = [target]
target_nodes = []
while dfs:
cur = dfs.pop()
target_nodes.append(cur)
if cur.left: dfs.append(cur.left)
if cur.right: dfs.append(cur.right)
return any(self.is_inversion(source,target_node) for target_node in target_nodes)