0007-reverse-integer.cs

public class Solution {
    public int Reverse(int x) {
        int rev = 0;
            
        while(x != 0) {
            var digit = x % 10;
            x = x / 10;
            if(rev > Int32.MaxValue / 10 || 
               // since max value is 2,147,483,647, 
               // last digit greater than 7 will overflow
              (rev == Int32.MaxValue / 10 && digit > 7)) 
                return 0;
            
            if (rev < Int32.MinValue/10 || 
                // since min value is  -2,147,483,648
                (rev == Int32.MinValue / 10 && digit < -8)) 
                return 0;
            
            rev = rev * 10 + digit;
        }
        
        return rev;
    }
}