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1.5.2 (latest release)
Spark
I can insert a string column to an iceberg UUID column thanks to #7399
df = df.withColumn("id", lit(str(uuid.uuid4())))
but I can't insert a byte column to an iceberg UUID column
df = df.withColumn("id", lit(uuid.uuid4().bytes))
thanks all
The text was updated successfully, but these errors were encountered:
@raphaelauv would you be interested in contributing a fix for this?
Sorry, something went wrong.
hey @nastra, I do not have the time to contribute this feature right now, thanks for the proposition 馃憤
until , I'm sharring an hacky bypass 馃槄 :
df = df.withColumn( "id", F.regexp_replace( F.lower(F.hex("id")), "(.{8})(.{4})(.{4})(.{4})(.{12})", "$1-$2-$3-$4-$5" ) )
I can give this a shot @nastra. Although I need to read the UUID PR first.
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Apache Iceberg version
1.5.2 (latest release)
Query engine
Spark
Please describe the bug 馃悶
I can insert a string column to an iceberg UUID column thanks to #7399
but I can't insert a byte column to an iceberg UUID column
thanks all
The text was updated successfully, but these errors were encountered: