0090-subsets-ii.java

//Similar to subsets 1. Here, we'll just take care of the duplicates.
//This video was helpful https://www.youtube.com/watch?v=mcg4qKbAmmY&t=316s&ab_channel=Fraz
class Solution {

    public List<List<Integer>> subsetsWithDup(int[] nums) {
        Arrays.sort(nums);
        List<List<Integer>> ans = new ArrayList<>();
        List<Integer> list = new ArrayList<>();
        subSet(nums, 0, ans, list);
        return ans;
    }

    public void subSet(
        int[] nums,
        int idx,
        List<List<Integer>> ans,
        List<Integer> list
    ) {
        ans.add(new ArrayList<>(list));

        for (int i = idx; i < nums.length; i++) {
            //skip the duplicate elements
            if (i > idx && nums[i] == nums[i - 1]) continue;
            list.add(nums[i]);
            subSet(nums, i + 1, ans, list);
            list.remove(list.size() - 1);
        }
    }
}