From 71f2e3a095194fcf8596a8baa36e2b08b6a88c8f Mon Sep 17 00:00:00 2001 From: Nicholas Nethercote Date: Tue, 13 Feb 2024 12:19:24 +1100 Subject: [PATCH] Optimize `delayed_bug` handling. Once we have emitted at least one error, delayed bugs won't be used. So we can (a) we can (a) discard any existing delayed bugs, and (b) stop recording any new delayed bugs. This eliminates a longstanding `FIXME` comment. There should be no soundness issues because it's not possible to un-emit an error. --- compiler/rustc_errors/src/lib.rs | 39 ++++++++++++++++++++++---------- 1 file changed, 27 insertions(+), 12 deletions(-) diff --git a/compiler/rustc_errors/src/lib.rs b/compiler/rustc_errors/src/lib.rs index e033d66fccf41..18cf64d937e3b 100644 --- a/compiler/rustc_errors/src/lib.rs +++ b/compiler/rustc_errors/src/lib.rs @@ -1275,6 +1275,9 @@ impl DiagCtxtInner { self.future_breakage_diagnostics.push(diagnostic.clone()); } + // Note that because this comes before the `match` below, + // `-Zeagerly-emit-delayed-bugs` continues to work even after we've + // issued an error and stopped recording new delayed bugs. if diagnostic.level == DelayedBug && self.flags.eagerly_emit_delayed_bugs { diagnostic.level = Error; } @@ -1286,18 +1289,20 @@ impl DiagCtxtInner { diagnostic.level = Bug; } DelayedBug => { - // FIXME(eddyb) this should check for `has_errors` and stop pushing - // once *any* errors were emitted (and truncate `delayed_bugs` - // when an error is first emitted, also), but maybe there's a case - // in which that's not sound? otherwise this is really inefficient. - let backtrace = std::backtrace::Backtrace::capture(); - // This `unchecked_error_guaranteed` is valid. It is where the - // `ErrorGuaranteed` for delayed bugs originates. - #[allow(deprecated)] - let guar = ErrorGuaranteed::unchecked_error_guaranteed(); - self.delayed_bugs - .push((DelayedDiagnostic::with_backtrace(diagnostic, backtrace), guar)); - return Some(guar); + // If we have already emitted at least one error, we don't need + // to record the delayed bug, because it'll never be used. + return if let Some(guar) = self.has_errors_or_lint_errors() { + Some(guar) + } else { + let backtrace = std::backtrace::Backtrace::capture(); + // This `unchecked_error_guaranteed` is valid. It is where the + // `ErrorGuaranteed` for delayed bugs originates. + #[allow(deprecated)] + let guar = ErrorGuaranteed::unchecked_error_guaranteed(); + self.delayed_bugs + .push((DelayedDiagnostic::with_backtrace(diagnostic, backtrace), guar)); + Some(guar) + }; } Warning if !self.flags.can_emit_warnings => { if diagnostic.has_future_breakage() { @@ -1363,6 +1368,16 @@ impl DiagCtxtInner { } if is_error { + // If we have any delayed bugs recorded, we can discard them + // because they won't be used. (This should only occur if there + // have been no errors previously emitted, because we don't add + // new delayed bugs once the first error is emitted.) + if !self.delayed_bugs.is_empty() { + assert_eq!(self.lint_err_guars.len() + self.err_guars.len(), 0); + self.delayed_bugs.clear(); + self.delayed_bugs.shrink_to_fit(); + } + // This `unchecked_error_guaranteed` is valid. It is where the // `ErrorGuaranteed` for errors and lint errors originates. #[allow(deprecated)]