From b314a3f3a53501860e68e861efb119e0567ad53a Mon Sep 17 00:00:00 2001 From: Asterisk <44215173+casnz1601@users.noreply.github.com> Date: Sun, 10 Oct 2021 11:35:48 +0800 Subject: [PATCH] =?UTF-8?q?Update=200108.=E5=B0=86=E6=9C=89=E5=BA=8F?= =?UTF-8?q?=E6=95=B0=E7=BB=84=E8=BD=AC=E6=8D=A2=E4=B8=BA=E4=BA=8C=E5=8F=89?= =?UTF-8?q?=E6=90=9C=E7=B4=A2=E6=A0=91.md?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit 补充python注释 --- ...11\346\220\234\347\264\242\346\240\221.md" | 42 ++++++++++++++----- 1 file changed, 31 insertions(+), 11 deletions(-) diff --git "a/problems/0108.\345\260\206\346\234\211\345\272\217\346\225\260\347\273\204\350\275\254\346\215\242\344\270\272\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.md" "b/problems/0108.\345\260\206\346\234\211\345\272\217\346\225\260\347\273\204\350\275\254\346\215\242\344\270\272\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.md" index f2bfbb3b86..e82d6e95b7 100644 --- "a/problems/0108.\345\260\206\346\234\211\345\272\217\346\225\260\347\273\204\350\275\254\346\215\242\344\270\272\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.md" +++ "b/problems/0108.\345\260\206\346\234\211\345\272\217\346\225\260\347\273\204\350\275\254\346\215\242\344\270\272\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.md" @@ -304,22 +304,42 @@ class Solution { } ``` -## Python +## Python +**递归** -递归法: ```python3 +# Definition for a binary tree node. +# class TreeNode: +# def __init__(self, val=0, left=None, right=None): +# self.val = val +# self.left = left +# self.right = right class Solution: def sortedArrayToBST(self, nums: List[int]) -> TreeNode: - def buildaTree(left,right): - if left > right: return None #左闭右闭的区间,当区间 left > right的时候,就是空节点,当left = right的时候,不为空 - mid = left + (right - left) // 2 #保证数据不会越界 - val = nums[mid] - root = TreeNode(val) - root.left = buildaTree(left,mid - 1) - root.right = buildaTree(mid + 1,right) - return root - root = buildaTree(0,len(nums) - 1) #左闭右闭区间 + ''' + 构造二叉树:重点是选取数组最中间元素为分割点,左侧是递归左区间;右侧是递归右区间 + 必然是平衡树 + 左闭右闭区间 + ''' + # 返回根节点 + root = self.traversal(nums, 0, len(nums)-1) return root + + def traversal(self, nums: List[int], left: int, right: int) -> TreeNode: + # Base Case + if left > right: + return None + + # 确定左右界的中心,防越界 + mid = left + (right - left) // 2 + # 构建根节点 + mid_root = TreeNode(nums[mid]) + # 构建以左右界的中心为分割点的左右子树 + mid_root.left = self.traversal(nums, left, mid-1) + mid_root.right = self.traversal(nums, mid+1, right) + + # 返回由被传入的左右界定义的某子树的根节点 + return mid_root ``` ## Go