This folder contains everything I used for the enigma challange.

Schlusselblatt is the codebook I created for cyberstorm. The first part is Army types, and the second half is navy types. I only really used army this year.

html/ gets updated and pushed to the pi to serve to the students to access.

index.odut was what I started the day with.
The final webpage is in html/, this is what was there at the end of cyberstorm.

enigma_machine.py was just a simple script, creating machines from the codebook, to check to make sure everything was working.
It is also useful to quickly encrypt a message for demoing.

if you encrypt: aaaaaaaaaaaaaaaaaaaaaaaaaa
with day 1 code from the codebook
you get			WUOHMWPIUTRHSUKNMUMYQGZTGO 
Which is useful to who how a number gets mapped to different numbers as the message is processed. The rotors turn with each keypress, so the encryption changes. This is why the nazis thought they had perfect encryption. The problem is a letter can not be encrypted to itself. notice that the encrypted message contains no a's. This was the primary weakness that was exploited.


The TCP challange was set up where two pi's send encrypted messages to each other. It was intended that the students would have to break the wifi encryption, then sniff the packets. The server would always end the message with the same thing "yes sir". This could be exploited if communicated to the students. Last year I had it set up with many different messages, this year I only had one long message.

Word of warning, I am 90% sure there is a bug when using the machine.set_display() method for very complex machines. Set the ring setting when making the machine instead.
I have not been able to replicate this bug, but two different students had this issue. So maybe caution away from the set_display() method? I still think the students were doing something wrong, but I still do not know what.



I wanted to have a challange where the students would have to break the encryption, only knowing that it was an army message. However, the numbers probably will not allow this to work. 

Restricted Army:

3 rotors and any position:		3*2*1=		6
rotor settings:					26*26*26=	17,576
Reflectors:						B or C		2
Plugboards:			26!/(6!*10!*2^10)=		150,738,274,937,250	

Total possible machines = 					31,792,511,043,565,272,000

31 quintillion
31 billion billion
...

So yeah, knew it got crazy when you factor in the plugboard.
But geez.


It is worse for navy

Rotor names			Enigma Models
I, II, III, IV, V	All Wehrmacht models
VI, VII, VIII		Kriegsmarine M3 & M4
Beta, Gamma			Kriegsmarine M4 (with thin reflectors)

So
3 OR 4 rotors, from a choice up to 10 rotors	(10*9*8)*(10*9*8*7)=	3,628,800
rotor settings:									26^3*26^4=				8,031,810,176
Reflectors:									B or C	or B-thin or C-thin	4
Plugboards (the same):							26!/(6!*10!*2^10)=		150,738,274,937,250	
Total possible machines = 												17,573,570,211,428,925,608,846,131,200,000

Now, this is a larger number than it actually is.
Because the b and c thin refelctors were only used with the beta and gamma rotors.
The math may not be quite right either, this was more of a napkin calculation.
But at this point the number is meaningless anyway.
17 nonillion
17 thousand billion billion billion