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Visualization of (continuous) secondary source contour by polygon #38

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@spors spors commented Jan 24, 2017

import numpy as np
import sfs

xs = [0, 2, 0]
grid = sfs.util.xyz_grid([-2.5, 2.5], [-2.5, 2.5], 0, spacing=0.02)
omega = 2*np.pi*1000

x0, n0, a0 = sfs.array.circular(200, 1.5)
d = sfs.mono.drivingfunction.wfs_2d_line(omega, x0, n0, xs)
a = sfs.mono.drivingfunction.source_selection_point(n0, x0, xs)
twin = sfs.tapering.tukey(a, 0.3)
p = sfs.mono.synthesized.generic(omega, x0, n0, d * a0 * twin, grid)

sfs.plot.soundfield(p, grid, xnorm=[0, 0, 0], vmin=-1.5, vmax=1.5)
sfs.plot.secondarysourcecontour_2d(x0, a)
sfs.plot.virtualsource_2d(xs)

grafik

@trettberg
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Two observations:

  • The contour has a gap.
  • The region of active sources is not symmetric. (Easier to see with few speakers, 16 or so).

@mgeier
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mgeier commented Jan 29, 2017

I guess this needs a closed parameter like sfs.array.weights_midpoint()?

@mgeier
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mgeier commented Jan 29, 2017

Possible fix for the second point made by @trettberg above: instead of line segments from one secondary source to the next, we should use line segments from halfway from the previous source to the current source to halfway to the next source. Again, the implementation could be similar to sfs.array.weights_midpoint().

@spors
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spors commented Feb 23, 2017

I have fixed the issue regarding the gap and the region of active secondary sources:

import numpy as np
import sfs
import matplotlib.pyplot as plt

xs = [5, 0, 0]

x0, n0, a0 = sfs.array.circular(20, 1.5)
a = sfs.mono.drivingfunction.source_selection_point(n0, x0, xs)

plt.figure(figsize=(10, 10))
sfs.plot.secondarysourcecontour_2d(x0, a)
sfs.plot.loudspeaker_2d(x0, n0, a, size=0.2)
sfs.plot.virtualsource_2d(xs)
plt.axis([-5.2, 5.2, -5.2, 5.2])

grafik

# add collection of lines to current axis
if ax is None:
ax = plt.gca()
plt.gca().add_collection(lc)
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This should be ax.add_collection(lc)

@mgeier
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mgeier commented Feb 24, 2017

Now it looks like the array is always closed, even if we don't want it to be:

sfs.plot.secondarysourcecontour_2d([(0, 0), (1, 1), (2, 1), (3, 0)],
                                   [False, True, True, False])
plt.axis('equal');

image

@hagenw
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hagenw commented Feb 27, 2017

Have the secondary sources to be connected by a line?
Under Matlab I solved the gap issue by using only points for plotting secondary sources. If the distance between them becomes very small then they appear as a line. If the distance is not small, points have the advantage that you still are able to see the actual distance.

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4 participants